draft

Climbing Flight

In climbing flight, T>DT>D, so the aircraft cannot maintain equilibrium in straight and level flight.

The aircraft ascends with climb angle γˉ\bar{\gamma}, with the horizontal component of the aircraft weight opposing the thrust.

Fig. 1: Forces on aircraft in a climb

Climb Angle

As for the glide angle, the climb angle can be determined by resolving forces perpendicular to the flight path

L=WcosγˉL=W\cos\bar{\gamma}

and parallel to the flight path

TD=WsinγˉT-D=W\sin\bar{\gamma}

and from trigonometry, the climb angle is simply

sinγˉ=TDW\sin\bar{\gamma}=\frac{T-D}{W}

the rate of climb is VclimbV_{climb} and is

Vclimb=Vsinγˉ=V(TD)WV_{climb}=V\sin\bar{\gamma}=\frac{V\left(T-D\right)}{W}

which gives the rate of increase of GPE

WVclimbRate of increaseof potential energy=TVThrustPowerDVDragPower\underbrace{W\cdot V_{climb}}_{\substack{\text{Rate of increase}\\\text{of potential energy}}} = \underbrace{T\,V}_{\substack{\text{Thrust}\\\text{Power}}} - \underbrace{D\,V}_{\substack{\text{Drag}\\\text{Power}}}

Climb Performance

The maximum climb angle requires the maximum excess thrust

The maximum rate of climb requires the maximum excess power

This should feel intuitively correct to you, based upon what we know about glide angle/rate and Dmin/PminD_{min}/P_{min} and - obviously - these do not occur at the same speed. These depend on the powerplant type, and individual engine characteristics.

For propeller and turbojet engines, there are some simplifications that can be made about the propulsor that allows easy determination of one of the parameters - excess thrust for a turbojet, and excess power for a turboprop.

Powerplant assumptions

For turbojet aircraft and low bypass ratio turbofan aircraft is is assumed that thrust remains constant with speed, and accordingly power increases with speed.

For turboprop aircraft and high bypass ratio turbofan aircraft is is assumed that power remains constant with speed, and accordingly thrust falls with speed.

Climb Curves - Turbojet

For a turbojet aircraft with a drag equation described by:

CD=CD0+KCL2C_D = C_{D0} + K\cdot C_L^2

with CD0C_{D0}=0.008, and KK=0.055, a wing area of 55m2\text{m}^2, a weight of 150kN, and a maximum lift coefficient of 1.55, capable of producing a thrust of 17kN at a given altitude, the climb rate and angles can be taken from the difference between the thrust available/required curves.

These plots are sensible to produce in EAS, for hopefully obvious reasons (if you’re unsure why, ask on Slack).

You can hover over the plots and check the values to see if you get the same answers as the ones I’ve produced.

Do your best to reproduce these plots as they may help you with a future homework - discuss on Slack and help each other if in doubt how to complete.

Interactive demo

Climb Curves - Turboprop

For the same aircraft, with a turboprop capable of producing a constant power of 1.7MW, the thrust and power curves can be shown similarly:

Climb Performance: Summary

The maximum climb rate is given by the maximum excess power. You can think of this as the exchange of thrust energy to GPE.

The maximum climb angle is given by the maximum excess thrust. This is where the least horizontal resistance is experienced.

Look at the table below. Confirm using the plots that this is correct.

Propeller AircraftJet Aircraft
Maximum Climb RateAt VmpV_{mp}>Vmp>V_{mp}
Maximum Climb Angle<Vmd<V_{md}At VmdV_{md}

Turboprops tend to have superior climb performance - but occurs at a lower speed.